2. (Chapter 13: Use rectangular coordinates)
The sliders A and B are connected by a light rigid bar of length l = 0.5 m and move with negligible friction in the horizontal slots shown (see Figure 2). For the position where xA = 0.4 m, the velocity of A is vA = 0.9 m/s to the right. At this instant
(a) draw the free-body-diagrams sliders A and B,
(b) determine the acceleration of the slider B, and
(c) determine the force in the bar.

Draw the schematic diagram of the sliders.
Calculate the length
.
Apply Pythagoras formula to calculate the length of the slider.
Here, l is the length of the bar.
Substitute 0.4 m for
and 0.5 m for l.
Again, apply Pythagoras formula to obtain the relation for the length of the slider.
…… (1)
Here, length of the rigid bar is
, distance of slider
is
and distance of slider
is
.
Obtain the relation the velocity of slider
by differentiating equation (1) with respect to t.
…… (2)
Substitute
for
,
for
and
for
.
Obtain the relation for the acceleration of slider
by differentiating equation (2).
Consider equation (2),
Differentiate the equation with respect to t.
Substitute
for
,
for
,
for
and
for
.
…… (3)
Draw the free body diagram of slider
.
Calculate the force acting along
-direction.
Here, angle of inclination is
and mass of slider
is
.
Substitute
for
and
for
in above equation.
…… (4)
Draw the free body diagram of slider
.
Calculate the force acting along
-direction.
Here, angle of inclination is
and mass of slider
is
.
Substitute
for
and
for
.
…… (5)
Calculate the acceleration of slider
by substituting equation (5) in equation (4).
Substitute equation (3) for
.
Substitute
for
.
Therefore, the acceleration of slider
is
.
Calculate the acceleration of slider
.
Thus, from equation (3),

Rewrite the equation as,
Substitute
for
.
Therefore, the acceleration of slider
is
Calculate the tension in the bar.
Substitute
for
.
Therefore, the tension in the bar is
.
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B2
B2
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