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How to calculate theoretical yield benzil in the hexaphenylbenzene experiment, with 0.753 g of benzoin produced.(molecular weight of benzil is 210.28 and amount used 100ml.)
Then theoretical yield of tetraphenylcyclopentadienon with 0.264 g of benzil product.
(molecular weight of tetraphenylcyclopentadienone is 384.48 and used 100 mg)
We are given, mass of benzoin = 0.753 g , molar mass of benzil = 210.28 g/mol
The reaction to find theoretical yield benzil is benzoin reacted with cupric acetate to create benzil.
So there is 1:1 mole ratio between benzoin and benzil
Step 1 ) Calculate the moles of benzoin
Moles = mass / molar mass
= 0.753 moles / 212.24 g.mol-1
= 0.00355 moles
Step 2) Calculating the moles of benzil from benzoin
We know there is mole ration between benzoin and benzil is 1:1
So, moles of benzoin = moles of benzil
So, moles of benzil = 0.00355 moles
Step 3 ) Calculate theoretical yield
Theoretical yield of benzil = 0.00355 moles * 210.28 g/mol
= 0.746 g
When benzil and 1,3 diphenylacetone reacted with CH3OH, [C6H5CH2N(CH3)3]+, OH- to create tetraphenylcyclopentadienone.
So, moles of benzil = moles of tetraphenylcyclopentadienon
So, moles of tetraphenylcyclopentadienon = 0.00355 moles
So theoretical yield of tetraphenylcyclopentadienon = 0.00355 moles * 384.48 g/mol
= 1.36 g
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