Question

An experiment was conducted to determine the rate law for the reaction A2(g)+B(g)→A2B(g) . The table above shows the data collected. Based on the data in the table, which statement is correct?

Trial 1 [A2] 0.10 [B] 0.50 0.20 0.50 Nm + Initial rate (Ms-1) 2.5 10-4 5.0 x 10-4 5.0 x 10-5 1.0 x 10-4 0.30 0.05 1 0.30 0.10 An experiment was conducted to determine the rate law for the reaction A2(g) +B(g) → A2B(g). The table above shows the data collected. Based on the data in the table, which statement is correct? (A) Since the rate law can be expressed as rate = k/A,12, tripling the concentration of A, will cause a 9-fold increase in the rate of the reaction. Since the rate law can be expressed as rate = k[A2][B], doubling the concentrations of A2 and B will quadruple the rate of the reaction. с Since the rate law can be expressed as rate = k[A12B), tripling the concentration of A, while keeping the concentration of B constant will triple the rate of the reaction. D) Since the rate law can be expressed as rate = k[A2]B]', doubling the concentration of B while keeping the concentration of A2 constant will double the rate of the reaction.

Answer 1

I Solution Az (9) + Bog) -> A2B (g) rate law, rate = K [AZ][B]" From experiment ① and ② the value of [B] is constant and [Ar ] varies rate, K[A2] [B]" rate, K[A2] [BJ2 p.5X164 K [0.107m = k [0.1076.50]" - Ko-2J" 6-57) 5.0x104 = [0.103" 0.5 [.2015 [0.5] = [0:53 ln (0.5) = m ln (0.5) - ln (0.5) m = In 10.50 = 1 CS Scanned with CamScanner

the value of [A2] is from experiment ♡ and constant and [B] varies ratez k [22] m / [B]h rateu k [22] [B]u (0.057m = K L0.30] 1.08104 K [0:39h (0.103" Co.05)" CS Scanned with Canos Saner = To.10)"

0.5 ln 0.5 = (0.5)" = nlnos = ln os - n - en as n = 1 so rate law I rate = K[A] [B] Ans- ® rate= k A2] [B], doubling the concentration of A, and B will quadruple the rate of the reaction.