Question

-22 HH 6/0° V The Norton current at terminals ab is: Select one: a. 120 A b. 1.5290 A C. 3290 A d. 1.52-90 A

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Answer #1

Norton's current is the short circuit current flowing through ab now when ab is shorted inductor is also shorted so current = 6(0)/-j2 = 3(90)

Where () represents phase angle

Thus c is correct

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