Below is the program to do the task..
You can use sizeof() function to get the memory used by the variable in program.. and if you know the type of the variable, use sizeof() again to get the memory used by that type and divide the two values to get the size of the array..
now use simple for loop to iterate through the array and use if statement to check if the value is equal to 6.0 and count the number of occurrences. Also maintain a sum(double) variable to sum the values along the array..
finally you have the total number of elements in the array and number of occurrences of 6.0 and total sum of all the elements..
Divide the sum by total number of elements to get average..
To display the double value upto 7 point of precision use "%.7f" in printf.. not a dot before 7
You can uncomment whatever value of array you want to use and comment out the value you dont want to use for verification or for submission.
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#include<iostream>
using namespace std;
int main(void){
//double fArray[]={1.0,2.0000012,3.0,6.0,4.0,5.0,7.0,6.0,8.0,9.0};
#include "Lab8AdataSetX.h"
//#include "Lab8datasample.h"
int len = sizeof(fArray)/sizeof(double);
int totalSixes =0;
double sum=0;
for(int i=0;i<len;i++){
if(fArray[i]==6)
totalSixes++;
sum+= fArray[i];
}
printf("array of size %d has %d occurrences of 6.0 \n",len,totalSixes);
printf("Average of the array is %.7f",sum/len);
return 0;
}
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