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We created a Cu/Zn cell by placing 0.10 M ZnSO4 in to a porous cup and...

We created a Cu/Zn cell by placing 0.10 M ZnSO4 in to a porous cup and poured 0.10 M CuSO4 in to a beaker surrounding the porous cup. We placed a Zn electrode in to the Zn solution and a copper electrode in the Cu solution.

a) Calculate the expected potential V (our measured potential V was around 1.09 so it should be around there I believe)
b) The e- flow from which electrode?

c) The e- flow to which electrode?

d) Which substance acts as the cathode?

We created a Cu/Zn cell by placing 0.10 M ZnSO4 in

I've attached a table of standard electrode potentials for half-reactions that we were provided.

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Answer #1

a)Oxidation at anode Zn(s) → Zn2+ (aq) + 2e- Reduction at cathode Cu2+(aq) + 2e--> Cu(s) Ecathode-+0.34V се = 0.34%-(-0.767)

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