Question

Request this to be done in JGrasp

1.Add a method to the program that calculates the cube of every number between a lower bound and an upper bound that a user inputs (for instance, lower bound 1 and upper bound 9, for between 1 and 9).

2. Write an additional method that return the cubed value of an integer

3.Write an additional method to accomplish the same thing in #1, but this time calls the method you wrote in #2

Answer 1

1 ans

methodd to the program that calculates the cube of a number is to be

Math.pow(m,n)

it is used to get the power of any base ,it will return m to the power of n (m^n).

program:

import java.util.*;
public class code
{
public static void main(String args[])
{
int lb,ub;/*lb=lower bound; ub=upper bound*/
System.out.println("enter lower bound");
Scanner in=new Scanner(System.in);
lb=in.nextInt();
System.out.println("enter upper bound");
ub=in.nextInt();

while(lb<ub)
{
lb=++lb;
System.out.println("cube of/n"+lb+"is:"+ Math.pow(lb, 3));
}
}
}

2 ans and 3 ans

additional method to return value of the integer

import java.util.*;
public class main
{
public static void main(String args[])
{
int lb,ub;
System.out.println("enter lower bound");
Scanner in=new Scanner(System.in);
lb=in.nextInt();
System.out.println("enter upper bound");
ub=in.nextInt();
cubedNumber(lb,ub);
}
public static int cubedNumber(int lb,int ub)
{
while(lb<ub)
{
lb=++lb;
System.out.println("cube of/n"+lb+"is:"+ Math.pow(lb, 3));
}
return lb;
}
}