Question

Create a class fully-qualified as edu.udc.cs 1. ArrayWork. This class should have a static method that takes an integer array with at least 1 element. All elements will be more than 0. The method must return a double array of the same size filled with normalized values at the same positions. Normalized values will be a value between 0 (exclusive) and 1 inclusive. Simply, it will be every input value divided by the maximum value in the input. For instance input[2,4,8] Must return a double array with the following values: [.25, 5, 1.0) The normalized values must correspond to the index in the input. We will discuss more details, including using the attached jar file to test your code. In your main, add edu.udc. cs 1. GUIUtils.do TheArray("myMeth"); where, myMeth is the name of the method you wrote in ArrayWork. If you've done everything correctly, you should see a nice message.

Answer 1

Here is the completed code for this problem. Comments are included, go through it, learn how things work and let me know if you have any doubts or if you need anything to change. If you are satisfied with the solution, please rate the answer. If not, PLEASE let me know before you rate, I’ll help you fix whatever issues. Thanks

Note: Since I don't have GUIUtils class mentioned, or any dependent classes, I cannot include any output.

//ArrayWork.java

package edu.udc.cs1;

public class ArrayWork {
        // required method
        public static double[] normalize(int[] array) {
                // creating a double array of same size
                double[] result = new double[array.length];
                // finding max value in array
                int max = array[0]; // initially assuming first element is the max
                // looping through rest of the elements, if any value > max, setting it
                // as the max
                for (int i = 1; i < array.length; i++) {
                        if (array[i] > max) {
                                max = array[i];
                        }
                }
                // now we loop through the array once again
                for (int i = 0; i < array.length; i++) {
                        // dividing element at index i in array by max value, storing result
                        // in result array at index i.
                        result[i] = (double) array[i] / max;
                }
                // finally returning result array
                return result;
        }
}