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Assume a transparent rod of diameter d = 6.55


Assume a transparent rod of diameter d = 6.55

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Answer #1

Critical angle is sin^

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Answer #2

Critical angle is sin^

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Answer #3

X=theta

Critical angle is

Xc=sin^-1(n_air/n_rod)

Xc =sin^-1(1/1.34)

Xc=48.27 degrees

The angle of reflection is

Xr =90-48.27 =41.73 degrees

Incident angle is

from snells law

Xi =sin^-1(n_rod*sin(xr)/n_air)

Xi =sin^-1(1.34*sin41.73/1)

Xi=63.12 degrees


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