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6. Calculate the activation energy (E) for the reaction N,Osta - 2 NO2 + O2(e) from the observed rate constants at the follow
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molek Solution - We know that - Arhenious eoh. k = A e RT Where K = rate Const Q = Activation energy (J) R = Gas Const. (8.31un (2-093x162) = ( 328 298 - 3.866 = $ ( 298 – 328 ) -3.866 X 328 X298 x R = -309 .: = 3.866 X 328 X298 X 8.314 T 30 Q = 1047Thanks!

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