Question

2. Two blocks of unknown mass my and m2 are made of the same material. The blocks are attached by a massless spring and sit on a frictionless surface. The spring is released, and each block moves away from the other and slides up a ramp. Block mis observed to slide up the left ramp and reach a height of hy. Block ma is observed to slide up the right ramp, which is not identical to the left ramp and reaches a height of ha. 10000000 ML X a. In terms of the given information and fundamental constants, find the ratio of m/my. (4) b. The experiment is repeated so that m, is secured to the surface and can't move. Compared to the original measured value of hy, the new value of h, will be: lower__higher unchanged. Justify your response. (2) c. Suppose a small amount of friction was present between the track and blocks, but was ignored by the experimenters. How would ratio m/my found in part a be affected? ma/m determined in part a is lower than the actual value. my/m, determined in part a is higher than the actual value. my/m, determined in part a is unaffected. Justify your choice. (3) d. Two new blocks of mass m= 0.5 kg and m, = 3 kg are placed on the frictionless track between the spring. The spring is compressed 0.02 m, and m moves off at 2 m/s. Find the k value of the spring. 3)

Answer 1

mmmal kommt When released Initial Momentom is conserved so Di = Pf o = M₂ V ₂ - MINI (Mivi= M2 V20 Apply energy conservation form, from A to B and for my from chod, formi, KEA IPEA = KEBAPER I'm, ut to = 0 + Migh v = √2ghi) - for Me Kect P E - K & + P. Eo IM₂ V to = 0 + might put v. and Va from @ & in (b) if M, is secured then the compressed PoE of spring is given to Only M2. so speed 1₂ of My will be more and from ear ② it V₂ is more than he will be more. Higher) answer (c) Some energy would have lost in friction. (c) Some enf= UN = wong frichon would be more for heavier block, and velocity of heavier block will be les so hequier block will go to less height as compared to smaller ho will decreve. (so mi will decreased er en oud to smaller os = 2 => [V2 = 3 m/s P.E of Spring = k.E of bocks. + x² - 1 min? t t me vet = 1X0.5x4 + 2 x 3 xq (k = 2 2 2 = 72500 N1 m.)

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