Question

10 kl 72 k.ft 1061 8* 72 k.lt 8 kips 2 k/ft

Draw the shear and moment diagrams

Answer 1

tok 72 kift v 76 Let VB, VE be the vertical reactions at supports B, E respectively. Calculation of support reactions * VatVE = 10+ 8 + 8 + 2x(4+4 VB TVE = 42 - 0 TEM -070 Algebraic sum of moments about TEMB= B is zero. ► VEX(6+4+4)= 8x(6+6+4+4) + 72 +8x4 +2x42 -2x4? solving we get IV = 18.86 kJ VB = 42-VE [from equation ] = 42 -18.86 TVB = 23.14k

shear force calculations (sf) ; (S.F) & 2 +8k +8-VE = +8 - 18.86 - - 10.86k cuj (SF)- (SF) = -10,86 k (iv) (S.Fc (just to the right of c) = = - 10.86+ 8 - 2.86k. (v) Shear force just to the fate right of B. (S.F) 2 = -2.86 + 2x4 = 5.14k (vi) Shear force just to the left of B SFR = 5:14 - VG + 10 =- 8k. in (SF) = 0. Bending moment calculations (BM) ) (BM) = 0 (11) (BM)= = - 8x6 = -48 kift a) (BM) [just to the right of D] = -8x (6+6) + VE X6 - – 8x12 + 18.8666 = 17.16 Koft

(iv) (B.m) (just to the better off) - 17.16 – 72 – – Kift. Vem)c = -8x(6+6+4) + Ve x[6+4) -72 – – 11.4 kift (vi) (B.MA=0 (ii) (B.m/2 = – 2x4 x 4 =- 16 kift "hoe - - - 1 stk 5.14 linear 2486 410.8 Shear diagam خانوار | 17.16 7 parabold line 1 parabola linear 54 Bending Moment diagram