Given q=1 B= i + j
The magnitude of force is given as F=qvB
= 1 x 19k x i + j = 19k(i +j)
=19 i + 19 j N
F = sqrt (192 + 192)
=26.87 N
According to the right-hand rule
When the magnetic force relationship is applied to a current-carrying wire,
This force will be perpendicular to Magnetic field.

A particle with unit charge (q = 1) enters a constant magnetic field B = i...
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