Homework Answers
the activation energy can also be calculated by using the arrhenius eqation instead of plotting a graph ( since plotting graph requires more than 6 experimental readings inorder to get accurate results)
please appreciate the method used.
by using the formula the
activation energies are calculated at various temperatures and
finally the mean activation energy is calculated which will be in
accordance with the graphical value .
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Given the following data for the following hypothetical reaction, determine the activation energy. You may upload...
The hypothetical reaction A(g)+B(g)->C(g)+D(g) was studied in order to determine its activation energy. The appropriate data...
The hypothetical reaction A(g)+B(g)->C(g)+D(g) was studied in
order to determine its activation energy. The appropriate data was
collected, analyzed, and graphed to produce the following graph.
Use the graph below to answer the questions:
a)What is the correct label for the x-axis
b)What is the correct label for the y-axis
c)What is the activation energy, in Kj/mol, for this
reaction?
Linear Fit for: Data Set IY y=mxeb m (Slope): -1435 [Y-intercept): 28.07 Correlation: -0.9970 RMSE: 0.1183 0.005 0.0045 0.004 0.0035
10. Given the following data for the reaction A B, determine the activation energy, En of...
10. Given the following data for the reaction A B, determine the activation energy, En of the reaction. (10 points) fenios 5) i imed T (K) SIA k (MIs) ELIATAS tvig ai olbd noitoe or ot wl o 6 CHEM 106L-General Chemistry II Lab Midterm Examination Fall 2019 0.681 ns 500 0020 1000 0.715 000 O02. 002s0 0002 0 002 0 021 0
Determine the rate law given for the following reaction given the initial rate data in the...
Determine the rate law given for the following reaction given the initial rate data in the table: 2A + 2BC+2D Experiment [A] (M) [B] (M) Initial rate (M/s) 0.0211 0.113 2.00 x 10-5 2 0.0422 0.113 8.00 x 10-5 3 0.0422 0.226 1.60 x 10 1 Rate = K[A] [B] Rate = K[A] [B] Rate - AllB12 Rate - [A] [B]
3) Determine the Activation Energy given the following data. Give a problem with running reactions at...
3) Determine the Activation Energy given the following data. Give a problem with running reactions at lower temps? Rate Constant (Molar-1Min.') 8.22 x 10-4 1.64 x 10-3 Temp (Degrees C) 25.00 C 35.00 C 3.28 x 10-3 45.00 C
•Using the data from Table 4: Reaction Rate Constants, you can now calculate the activation energy...
•Using the data from Table 4: Reaction Rate Constants, you can
now calculate the activation energy for the reaction.
•Calculate the activation energy using the equation
below.
•You will calculate the activation energy 3 times by using the
data from:
•Reactions 1+5
•Reactions 1+6
•Reactions 5 + 6
•You will calculate the average activation energy for the
reaction.
k1 Ea 1 1 In ( ) T Where: ki = rate constant at T1 kzi = rate constant at T2 T1...
Table 3: Experimental Data for Part 2: Determination of Activation Energy k Time* T* [1] [S,0,?]...
Table 3: Experimental Data for Part 2: Determination of Activation Energy k Time* T* [1] [S,0,?] Rate (M/s) (s) (C) (M) (M) Run 3 153 20.5 .0208 .0416 4.03*10^-6 4.65*10^-3 (Room T) Run 6 198 9 .0208 .0416 3.15*10^-6 3.64*10^-3 (Cool) Run 7 112 31 .0208 .0416 5.58*10^-6 6.45*10^-3 (Warm) Run 8 40 51 .0208 .0416 1.56*10^-5 1.80*10^-2 (Warmer) 1/T (1/K) In k Run 3 1/293.5 -5.37 Run 6 1/282 -5.62 Run 7 1/304 -5.044 Run 8 1/324 -4.02 20....
Rate Determination and Activation Energy DATA TABLE Trial Temperature (°C) Rate constant, (S-1) 0.00157 24 0.007435...
Rate Determination and Activation Energy DATA TABLE Trial Temperature (°C) Rate constant, (S-1) 0.00157 24 0.007435 2 16 3 11 0.005563 4 1. Po above, using Temperce ahd. the rate сон dik, as they axis. 2. Determine the activation energy, Ea, by plotting the natural log of k vs. the reciprocal of absolute temperature. You can calculate 1/T (first convert T to K) and in k manually, or use Excel to do it. You will also need to make a...
Applicati 6. For a generic reaction A + B C, the following data are obtained Experiment...
Applicati 6. For a generic reaction A + B C, the following data are obtained Experiment Initial /AL. M Initial (e). M Initial rate (M/s 0.100 M 0.100 M 0.100 M 0.200 M 16.0 x 10 16.0 x 10 0200 M 0,100M 64.0 x10 64.0 x 10 0.100 M a. (5 pts) Based on the data, what is the rate law for the reaction? b. (5 pts) using experiment #2's data, solve for k. (5 pts) For experiment #2, after...
thanks in advance ☺ (A). For the hypothetical reaction A+B → C the following rate data...
thanks in advance ☺
(A). For the hypothetical reaction A+B → C the following rate data (with and without catalyst) were obtained: Rate, M/s Rate, M/s (A), M [B, M (uncatalyzed) (catalyzed) 0.100 0.200 3.51 x 10 4 7.14 x 10-2 0.100 0.100 1.75 x 104 7.14 x 10-2 0.0500 0.200 1.76 x 104 3.57 x 10-2 0.0500 0.100 8.80 x 10-5 3.57 x 10-2 Based on these data: a. Determine the uncatalyzed and catalyzed rate laws for this reaction,...
Question 16 (3 points) Given the following data for the reaction Y → B, determine the...
Question 16 (3 points) Given the following data for the reaction Y → B, determine the activation energy, Ea, of the reaction. k(M/s) TOK 50 2.04 x 10-4 6.78 x 10-3 400 2.34 kJ/mol 19.4 kJ/mol 38.2 kJ/mol 2.02 kJ/mol 18.6 kJ/mol
The hypothetical reaction A(g)+B(g)->C(g)+D(g) was studied in
order to determine its activation energy. The appropriate data was
collected, analyzed, and graphed to produce the following graph.
Use the graph below to answer the questions:
a)What is the correct label for the x-axis
b)What is the correct label for the y-axis
c)What is the activation energy, in Kj/mol, for this
reaction?
Linear Fit for: Data Set IY y=mxeb m (Slope): -1435 [Y-intercept): 28.07 Correlation: -0.9970 RMSE: 0.1183 0.005 0.0045 0.004 0.0035
10. Given the following data for the reaction A B, determine the activation energy, En of the reaction. (10 points) fenios 5) i imed T (K) SIA k (MIs) ELIATAS tvig ai olbd noitoe or ot wl o 6 CHEM 106L-General Chemistry II Lab Midterm Examination Fall 2019 0.681 ns 500 0020 1000 0.715 000 O02. 002s0 0002 0 002 0 021 0
Determine the rate law given for the following reaction given the initial rate data in the table: 2A + 2BC+2D Experiment [A] (M) [B] (M) Initial rate (M/s) 0.0211 0.113 2.00 x 10-5 2 0.0422 0.113 8.00 x 10-5 3 0.0422 0.226 1.60 x 10 1 Rate = K[A] [B] Rate = K[A] [B] Rate - AllB12 Rate - [A] [B]
3) Determine the Activation Energy given the following data. Give a problem with running reactions at lower temps? Rate Constant (Molar-1Min.') 8.22 x 10-4 1.64 x 10-3 Temp (Degrees C) 25.00 C 35.00 C 3.28 x 10-3 45.00 C
•Using the data from Table 4: Reaction Rate Constants, you can
now calculate the activation energy for the reaction.
•Calculate the activation energy using the equation
below.
•You will calculate the activation energy 3 times by using the
data from:
•Reactions 1+5
•Reactions 1+6
•Reactions 5 + 6
•You will calculate the average activation energy for the
reaction.
k1 Ea 1 1 In ( ) T Where: ki = rate constant at T1 kzi = rate constant at T2 T1...
Table 3: Experimental Data for Part 2: Determination of Activation Energy k Time* T* [1] [S,0,?] Rate (M/s) (s) (C) (M) (M) Run 3 153 20.5 .0208 .0416 4.03*10^-6 4.65*10^-3 (Room T) Run 6 198 9 .0208 .0416 3.15*10^-6 3.64*10^-3 (Cool) Run 7 112 31 .0208 .0416 5.58*10^-6 6.45*10^-3 (Warm) Run 8 40 51 .0208 .0416 1.56*10^-5 1.80*10^-2 (Warmer) 1/T (1/K) In k Run 3 1/293.5 -5.37 Run 6 1/282 -5.62 Run 7 1/304 -5.044 Run 8 1/324 -4.02 20....
Rate Determination and Activation Energy DATA TABLE Trial Temperature (°C) Rate constant, (S-1) 0.00157 24 0.007435 2 16 3 11 0.005563 4 1. Po above, using Temperce ahd. the rate сон dik, as they axis. 2. Determine the activation energy, Ea, by plotting the natural log of k vs. the reciprocal of absolute temperature. You can calculate 1/T (first convert T to K) and in k manually, or use Excel to do it. You will also need to make a...
Applicati 6. For a generic reaction A + B C, the following data are obtained Experiment Initial /AL. M Initial (e). M Initial rate (M/s 0.100 M 0.100 M 0.100 M 0.200 M 16.0 x 10 16.0 x 10 0200 M 0,100M 64.0 x10 64.0 x 10 0.100 M a. (5 pts) Based on the data, what is the rate law for the reaction? b. (5 pts) using experiment #2's data, solve for k. (5 pts) For experiment #2, after...
thanks in advance ☺
(A). For the hypothetical reaction A+B → C the following rate data (with and without catalyst) were obtained: Rate, M/s Rate, M/s (A), M [B, M (uncatalyzed) (catalyzed) 0.100 0.200 3.51 x 10 4 7.14 x 10-2 0.100 0.100 1.75 x 104 7.14 x 10-2 0.0500 0.200 1.76 x 104 3.57 x 10-2 0.0500 0.100 8.80 x 10-5 3.57 x 10-2 Based on these data: a. Determine the uncatalyzed and catalyzed rate laws for this reaction,...
Question 16 (3 points) Given the following data for the reaction Y → B, determine the activation energy, Ea, of the reaction. k(M/s) TOK 50 2.04 x 10-4 6.78 x 10-3 400 2.34 kJ/mol 19.4 kJ/mol 38.2 kJ/mol 2.02 kJ/mol 18.6 kJ/mol
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