m = 0.3kg, A = 0.1m, T = 0.5s, k = 47.4 N/m
w = 12.57 rad/s, E = 0.237 J
e. What is velocity at 0.05m?
Answer is 1.09 m/s. How do I solve this?
Total mechanical energy = 0.237 J
Energy is conserved therefore,


Solving we get,

You toss a 0.90kg M-80 into the sky with a velocity 3.9m/s i^+ 9.9m/s j^ at t= 0s . At t= 0.61s the M-80 explodes into two unequal chunks of m1= 0.3kg and m2= 0.6kg . Ignore any air resistance. What is the y -component of the M-80's velocity immediately before the explosion?
find G1(s)=theta 1(s)/ T(s)
I N-m/rad 0200) T(C) I N-m/rad 1 kg-m2 1 N-m-s/rad 1 N-m-s/rad
I N-m/rad 0200) T(C) I N-m/rad 1 kg-m2 1 N-m-s/rad 1 N-m-s/rad
r(m) = 0.36 k(N/m) = 414 m(kg) = 23 x1(m)= 0.350
x2(m)=0.350 x3(m) = 0.700
Q0(deg)=50 Q1(deg)=7 ()0 (rad/s)=2
() (rad/s)=7
4. (25 points) The lever OĂ, which has mass m and radius of gyration r about O, has an angular velocity w = w, when 0 = 0. The attached spring has a stiffness k and it is unstretched when 0 =(when the lever is vertical). Calculate the constant moment M applied to the lever which will give the...
How
do I solve?
A0.500 kg mass is oscillating on a spring with k 330 N/m. The total energy of its oscillation is 3.24 J What is the speed of the mass when it is 0.100 m from the EP? (Unit m/s) Enter 3-209 Acelhus Corporation. All Rights Reperved
The two springs, each of stiffness k 1.09 kN/m, are of equal length and undeformed when 0-0. If the mechanism is released from rest in the position e-27°, determine its angular velocity when e-0. The mass m of each sphere is 2.4 kg. Treat the spheres as particles and neglect the masses of the light rods and springs 0.40 m Answer: 0 rad/s
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just need help with the last one, i)
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