| Group | ni | x̅i | S2i | ni*(Xi-Xgrand)2 | SS |
| 1 | 107 | 2.000 | 2.46 | 104.661 | 261.2794 |
| 2 | 255 | 3.300 | 2.82 | 24.662 | 716.8896 |
| 3 | 313 | 3.090 | 2.86 | 3.192 | 891.1032 |
| 4 | 32 | 2.830 | 3.46 | 0.809 | 107.2476 |
| grand mean= | 2.989 | Total | 133.3247 | 1976.5198 | |
| SSTr | SSE | ||||
| Source | SS | df | MS | F | |
| Treatment | 133.3247 | 3 | 44.4416 | 15.8068 | |
| error | 1976.5198 | 703 | 2.8116 | ||
| total | 2109.8445 | 706 |
from above F =15.81


Suppose the accompanying summary statistics for a measure of social marginality for samples of youths, young...
Suppose samples of six different brands of diet or imitation margarine were analyzed to determine the level of physiologically active polyunsaturated fatty acids (PAPUFA, in percent), resulting in the data shown in the accompanying table. Imperial 14.1 13.6 14.4 14.3 Parkay 12.8 12.5 13.4 13.0 12.3 Blue Bonnet 13.5 13.4 14.1 14.3 Chiffon 13.2 12.7 12.6 14.1 Mazola 16.8 17.2 16.4 17.3 18.0 17.2 18.7 18.4 Fleischmann's 18.1 (a) Test for differences among the true average PAPUFA percentages for the...
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1 Consider the following summary data on the modulus of elasticity ( 105 psi) for lumber of three different grades. Grades 1.64 0.21 2 1.54 0.23 3 71.42 0.22 Use this data and a significance level of 0.01 to test the null hypothesis of no difference in mean modulus of elasticity for the three grades. Calculate the test statistic. (Round your answer to two decimal places.) What can be said about the P-value for the test? OP-value > 0.100 0.050...
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Consider the following summary data on the modulus of elasticity
(✕ 106 psi) for lumber of three different grades.
Grade
J
xi.
si
1
11
1.61
0.22
2
11
1.55
0.23
3
11
1.42
0.21
Use this data and a significance level of 0.01 to test the null
hypothesis of no difference in mean modulus of elasticity for the
three grades. Calculate the test statistic. (Round your answer to
two decimal places.)
f =
What can be said about the...
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1. In an experiment to compare the tensile strengths of 1 - 6 different types of copper wire, ) = 5 samples of each type were used. The between-samples and within samples estimates of a were computed as MSTR = 2649.3 and MSE - 1169.2, respectively. Use the F test at level 0.05 to test Ho: H1 12 - ... - versus Ha: at least two wi's are unequal Calculate the test statistic (Round your answer to two decimal places.)...