Question

1.Write a function called high_point that takes a list of integers and returns True if there exists a value in the list that is bigger than the values immediately before and after it in the list. Your function must return False if no such value exists. The values in the beginning and the end of the list cannot be high points. (20 points)

Test Cases:

print(high_point([2,5,8,9,7,9])) True

print(high_point([2,5,6,6,3])) False

print(high_point([2,5,8,21,22])) False

2. Write a while loop to repeatedly ask for an integer between 0 and 9. Keep count of how many times each value occurs in a list and end the loop when any value reaches 3 occurrences, at which point you should print out the list of occurrences. You can assume that the user always enters an integer value, but must verify that the value lies within the correct range. If an invalid value is entered, simply ignore it and go to the next input.

Here is a sample run:

Enter a digit (0-9): 4

Enter a digit (0-9): 9

Enter a digit (0-9): 1

Enter a digit (0-9): 2

Enter a digit (0-9): -1

Enter a digit (0-9): 10

Enter a digit (0-9): 6

Enter a digit (0-9): 1

Enter a digit (0-9): 1

[0, 3, 1, 0, 1, 0, 1, 0, 0, 1]

Answer 1

# 1st program
def high_point(num_list):
    # Iterate loop from index 1 to 1 less than length
    # First value and last value cannot be high point
    for i in range(1, len(num_list) - 1):
        # If a value at index i > value at index i-1 and i+1, return true
        if num_list[i] > num_list[i - 1] and num_list[i] > num_list[i + 1]:
            return True

    return False  # Return false after loop


# Test cases
print(high_point([2, 5, 8, 9, 7, 9]))
print(high_point([2, 5, 6, 6, 3]))
print(high_point([2, 5, 8, 21, 22]))
print()
# 2nd program
# Create a list to store occurence of digits from 0-9
# List indices starts from 0. So for list of length 10, index are 0-9
occurrence = [0] * 10

# Iterate loop till occurrence list doesn't have 3 in it
# which means no digit has appeared 3 times
while 3 not in occurrence:
    digit = int(input('Enter a digit (0-9): '))  # Ask to enter a digir
    if digit < 0 or digit > 9:  # If not valid, continue to ask another digit and do nothing
        continue
    occurrence[digit] += 1  # Increment value at index digit by 1

print(occurrence)  # Print occurrence list

SCREENSHOT

M HighPoint.py X # 1st program def high_point (num_list): # Iterate loop from index 1 to 1 less than length # First value and last value cannot be high point for i in range (1, len (num list) - 1): # If a value at index i > value at index i-1 and i+1, return true if num_list[i] > num_list[i - 1] and num_list[i] > num_list[i + 1]: return True DD1- 0 1 - CO2 1 return false # Return false after loop # Test cases print (high_point ([2, 5, 8, 9, 7, 9])) print (high_point ([2, 5, 6, 6, 3])) print (high_point ([2, 5, 8, 21, 22])) print() 16 17 18 20 # Create a list to store occurence of digits from 0-9 # List indices starts from 0. So for list of length 10, index are 0-9 occurrence = [0] * 10 21 23 24 25 # Iterate loop till occurrence list doesn't have 3 in it # which means no digit has appeared 3 times while 3 not in occurrence: digit = int(input('Enter a digit (0-9): ')) # Ask to enter a digir if digit <0 or digit > 9: # If not valid, continue to ask another digit and do nothing continue occurrence [digit] += 1 # Increment value at index digit by 1 28 29 30 31 print (occurrence) # Print occurrence list

OUTPUT

HighPoint E:\Practice Python\venv\Scripts\python.exe True False False Enter a digit (0-9): 4 Enter a digit (0-9): 9 Enter a digit (0-9): 1 Enter a digit (0-9): 2 Enter a digit (0-9): -1 Enter a digit (0-9): 10 Enter a digit (0-9): 6 Enter a digit (0-9): 1 Enter a digit (0-9): 1 [0, 3, 1, 0, 1, 0, 1, 0, 0, 1] Process finished with exit code 0