1 A solution is prepared by dissolved 65.0 grams of a molecular unknown in 200.0 grams...
5. 1.024 g of an unknown molecular solid are dissolved in enough
water to produce 200.0 mL of solution. The osmotic pressure at 25C
is 278.0 torr. What is the molar mass of the solid?
6a. Calculate the van't Hoff factor of a 0.085M potassium
sulfate solution that has an osmotic pressure of 5.4atm at
25C
5. 1.024 g of an unknown molecular solid are dissolved in enough water to produce 200.0 ml. of solution. The osmotic pressure at 25...
5. 1.024 g of an unknown molecular solid are dissolved in enough water to produce 200.0 mL of solution. The osmotic pressure at 25°C is 278.0 torr. What is the molar mass of the solid? 1342.5 g/mol
When 0.60 grams of a non-electrolyte unknown compound is dissolved in 10 grams of water, the freezing point of the solution is -1.86o C. Given that the freezing point of pure water is 0o C and that the freezing-point depression constant for water is 1.86 o C/mol/kg, calculate the molecular mass (g/mol) of the unknown compound.
. 0.275 L of solution is prepared by dissolving 2.50 g of an unknown molecular compound in enough water. The osmotic pressure of this solution is 1.98 atm at 27 °C. (R = 0.08206 L·atm/mol·K) a) Determine the molar mass of the molecular compound. (7 pts) b) If you need to prepare 0.275 L of AlCl3 solution with the same osmotic pressure of the above solution, what mass of AlCl3 (MW = 133.33 g/mol) would you need to weigh out?
A researcher dissolved 1.50 grams of an unknown compound in 75.0 grams of pure cyclohexane. The freezing point of the solution was measured to be 2.70 °C. Knowing the freezing point of cyclohexane is 6.50 °C and the freezing point constant is -20.2 °C kg/mol, calculate the molar mass of the unknown compound.
3a. Calculate the molar mass (in g/mol) of an unknown 1:1 electrolyte if 0.482 g dissolved in 223.1 mL of water at 74.75 °C has an osmotic pressure of 54.4 mmHg. R = 0.082058 L⋅atm⋅mol−1⋅K−1. 1.00 atm = 760 mmHg. Report your answer to THREE significant figures. 3b. Calculate the required mass of an unknown nonelectrolyte (ℳ = 131.5599 g/mol) dissolved in 140.1 g of solvent that gives a solution that boils at 36.04 °C. The boiling point of the...
1.When a solution is made from 32.2 g of an unknown nonelectrolyte dissolved in 151 g of solvent, the solution boils at 83.44 °C. The boiling point of the pure solvent and its Kb are 79.31 °C and 4.47 °C/m, respectively. Calculate the molar mass of the unknown electrolyte in g/mol. 2. Calculate the molar mass (in g/mol) of an unknown nonelectrolyte if 0.898 g dissolved in 268.7 mL of water at 30.13 °C has an osmotic pressure of 68.1...
0.2650 g of a compound of unknown molecular mass were dissolved in 18.00 mL of a non-ionizing solvent with specific gravity of 0.7480. The pure solvent was determined to have a freezing point of 6.80°C. The freezing point of the solution was determined graphically. Trial one yielded a freezing point of 5.31°C for the solution. Trial two indicated the freezing point to be 5.23°C. Kf (solvent) = 12.8 C°/m a. Calculate the molecular mass of the unknown. b. If 5.50...
Colligative Properties 1a When a solution is made from 25.9 g of an unknown nonelectrolyte dissolved in 167.6 g of solvent, the solution boils at 63.24 °C. The boiling point of the pure solvent and its Kb are 59.02 °C and 2.09 °C/m, respectively. Calculate the molar mass of the unknown electrolyte in g/mol. Report your answer to TWO places past the decimal 1b When a solution is made from 39.5 g of an unknown nonelectrolyte dissolved in 109.1-2.47 °C....
ow many grams of sucrose are needed to decrease the temperature of 200.0 mL of water by 1.2 °c, solution freezing point is -1.2°C? Assume the density of water is 1.0 g/mL 4. What is the molar mass of a molecule when 12.5 grams of the molecule is dissolved in 0.500 kg of water and the boiling point of the solution is 100.3 °C?