


For x-1 and the given stress matrix What is the x-component of the traction vector acting...
1. The stress at a point in a solid is found to be 4 1 2 0;; = 1 8 -2 - 12- 22 (1) Determine the traction vector on a surface with 1. 2. 2 unit normal n =-, +-e, --ez, 3 3 3 (2) Determine the component of this traction vector acting perpendicular to the plane. (3) Determine the share component of this traction vector.
The stress state in a body is given by the following matrix with reference to x-y-z 4 2 0 0 08 coordinates, 2 4 0 ksi. Determine the stress vector acting on the shaded plane in the reference cube below
1) What are the x and y components of this vector?
x-component:
2) y-component
3)The x component of a vector is 12.5 m and the y component of a
vector is 25 m. What is the magnitude and direction (with respect
to the positive x-axis) of this vector?
magnitude:
4)direction:
A vector has a magnitude of A = 16.5 m and makes an angle of 0 = 5.4 ° with the negative x-axis. A
1.) Vectors Can the x or y component of a vector ever have a greater magnitude than the vector itself has? Yes. The x component can, but the y component cannot. Yes, but only when the x and y components have equal magnitudes. Yes. Both components can. Yes. The y component can, but the x component cannot. No. Neither component can. 2.) A force vector has a magnitude of 370 newtons (N) and points at an angle of 53.0° below...
The x vector component of a displacement vector has a magnitude of 97.7 m and points along the negative x axis. The y vector component has a magnitude of 168 m and points along the negative y axis. Find (a) the magnitude and (b) direction of 7. Specify the direction as a positive angle with respect to the negative x axis. (a) Number Units (b) Number Units
Prob #4: The Mohr circle associated with x-y state of stress on a component is shown below (not necessarily to scale). 5.0 28p D(si) 20 Tiksi) 61 ksi Component Yield Stress in magnitude on planes whose The component is subjected to shear stress of ~ normal is along x or y directions A)2.8 B)56C)6.1 D) 8 E)10 F)12.2 ks G)18.3 G)3.7 14. H)20 l)24.4 )26.2 - 15. Based on the Max. Principal Stress Theory, the factor of safety for yielding...
Question 1 1 pts Given the moment acting on the rectangular section, determine the magnitude of its component acting about the y-axis. Provide your answer in Nm, but do not include units in your answer. 30° HY A B N front M=250 Nim с D D Question 2 1 pts Given the moment acting on the rectangular section in Question 1, determine the magnitude of its component acting about the z-axis. Provide your answer in Nm, but do not include...
4 Stress Tensor 1. Given: T=14 1 01 MPa. 0 0 1 (a) find the stress vector on the plane whose normal is in the direction of +ý (b) Find the normal stress on the same plane. (c) Find the magnitude of the tangential stress on the same plane. (d) Find the three principal directions of stress. Hint: the determinant of a 3 x3 11 a12 13 det a a2 a23a11 (a22033-a3223) a12 a1a33-a31a23)+a13(a2132-a31022) 031 a32 33 Given the following...
Vector A has a negative x component 3.30 units in length and a positive y component 2.02 units in length (a) Determine an expression for A in unit-vector notation. j) units (b) Determine the magnitude and direction of A magnitude direction unit(s) o counterclockwise from the positive x axis (e) what vector B when added to vector A, gives a resultant vector with no x component and a negative y component 4.14 units in length? j) units
The state of stress at a point on a body is given by the following stress components: 0 = 15 MPa, Oy = -22 MPa and Try = 9 MPa Matlab input: sx = 15; sy = -22; txy = 9; 1) Determine the principal stresses 01 and 02. 1 = MPa 02= MPa 2) Sketch the principal stress element, defined by the rotation @pl. y Enter the rotation @pi (-360º < Opl < 360°): Opl = Add stress components:...