For the reaction below, 11.2 g of triglyceride (MW = 762.0 g/mol) and 52.0 mL of...
For the reaction below, 11.2 g of triglyceride (MW = 762.0 g/mol) and 52.0 mL of 6.0 M NaOH was used. How many mols of base will be left over once the reaction has completed? (Answer to the Ten Thousandths)
Reaction: glyceryl tripalmitate + 3 NaOH --> 3 sodium palmitate + glycerol
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For the reaction below, 11.2 g of triglyceride (MW = 762.0
g/mol) and 52.0 mL of...
How many mL of glycerol (MW=92.1 g/mol, density 1.26 g/mL) must be used to prepare 250.0...
How many mL of glycerol (MW=92.1 g/mol, density 1.26 g/mL) must be used to prepare 250.0 mL of a 0.150 M glycerol solution? Answer: 2.74mL glycerol
Sodium hydroxide is standardized by a reaction with potassium hydrogen phtalate (KHP, MW 2042 g/mol). Calculate...
Sodium hydroxide is standardized by a reaction with potassium hydrogen phtalate (KHP, MW 2042 g/mol). Calculate the molarity of a NaOH solution if 0.5123 g KHP were titrated to the equivalence point with 22.75 mL solution of NaOH. 0.0002509 moll Ob 0.02275 moll O c.0.1103 mol/l Od 1.10 mol/l
2 dibenzalacetone acetone benzaldehyde MW- 106.13 g/mol bp-1 78°C d 1.04 g/mL MW 234.30 g/mol mp #110-1110 MW-58.08 g/mol bp 56°C d 0.79 g/mL Its bs Reaction Setup (3 pts) S. OS Initial quant...
2 dibenzalacetone acetone benzaldehyde MW- 106.13 g/mol bp-1 78°C d 1.04 g/mL MW 234.30 g/mol mp #110-1110 MW-58.08 g/mol bp 56°C d 0.79 g/mL Its bs Reaction Setup (3 pts) S. OS Initial quantity of NaOH: S. I Initial quantity of benzaldehyde: mL Initial quantity of acetone: mL Theoretical yield of dibenzalacetone based on benzaldehyde: (show calculations) Theoretical yield of dibenzalacetone based on acetone 9 (show calculations) ce tone Limiting Reagent: Product Data (10 pts) fivAL Mass: 3.3g Percent Yield:...
You wish to prepare 100.0 mL of a 325.0 ppm w/v sodium (MW = 22.9897 g/mol)...
You wish to prepare 100.0 mL of a 325.0 ppm w/v sodium (MW = 22.9897 g/mol) solution. How many grams of sodium dichromate dihydrate (Na2Cr2O7·2H2O, MW = 297.998 g/mol) are needed to prepare this solution? Assume the final solution has a density of 1.00 g/mL.
Materials: NaOH MW = 40 g/mL, KHP - potassium hydrogen phthalate, KHC8H404, MW = 204.23 g/mol....
Materials: NaOH MW = 40 g/mL, KHP - potassium hydrogen phthalate, KHC8H404, MW = 204.23 g/mol. Acetic acid, HC2H302, MW = 60.05 g/mol Part 1: Standardization of NaOH Assume 0.951 g of KHP is weighed and transferred to a 250 mL Erlenmeyer flask. Approximately 50 ml water is added to dissolve the KHP. Note that the exact volume of water is not important because you only need to know the exact number of moles of KHP that will react with...
How many grams of Na3PO4 (MW = 164 g/mol) are needed to make 282.3 mL of...
How many grams of Na3PO4 (MW = 164 g/mol) are needed to make 282.3 mL of solution that is 0.200 M sodium?
Materials: NaOH MW = 40 g/mL, KHP - potassium hydrogen phthalate, KHC8H404, MW = 204.23 g/mol....
Materials: NaOH MW = 40 g/mL, KHP - potassium hydrogen phthalate, KHC8H404, MW = 204.23 g/mol. Acetic acid, HC2H302, MW = 60.05 g/mol Part 1: Standardization of NaOH Assume 0.951 g of KHP is weighed and transferred to a 250 mL Erlenmeyer flask. Approximately 50 ml water is added to dissolve the KHP. Note that the exact volume of water is not important because you only need to know the exact number of moles of KHP that will react with...
5.8 g of 1,4-di-t-butyl-2,5-dimethoxynezene (250.37 g/mol) were synthesized by reacting 10.5 mL of t-butyl alcohol (MW...
5.8 g of
1,4-di-t-butyl-2,5-dimethoxynezene
(250.37 g/mol) were synthesized by reacting
10.5 mL of t-butyl alcohol (MW 74.12 g/mol, D
0.79 g/mL), 25 mL of concentrated sulfuric
acid (MW 98.08 g/mol, D 1.84
g/mL), and 5.9 g of 1,4-dimethoxybenzene (MW
138.17 g/mol) together. Calculate the percent
yield of this reaction.
Question 1 2 pts 5.8 g of 1,4-di-t-butyl-2,5-dimethoxynezene (250.373/mol) were synthesized by reacting 10.5 mL oft- butyl alcohol (MW 74.12 3/mol. D 0.795/mL), 25 mL of concentrated sulfuric acid (MW 98.08...
8. If the reaction shown was carried out by allowing 7.50 mL of 2,2,3-trimethyl-3-pentano (MW=130.23 g/mol,...
8. If the reaction shown was carried out by allowing 7.50 mL of 2,2,3-trimethyl-3-pentano (MW=130.23 g/mol, d 0.857 g/mL) to react with catalytic acid to generate 3,4,4-trimethyl-2-pentene (MW=112.21 g/mol) and water, what is the theoretical yield (in grams) of the alkene product? (15 pts) OH H₂O H3PO4 + 4, 60 min 3,4,4-trimethyl-2-pentene 2,2,3-trimethyl-3-pentano 7. 50mL 15% 857 - 8.75 - 10 150.23 knool 112.215
Calculate the osomolarity of 0.5 g/mL of magnesium sulfate heltahydrate (MgSO4*7H2O) MW= 246.47 g/mol Calculate the o...
Calculate the osomolarity of 0.5 g/mL of magnesium sulfate
heltahydrate (MgSO4*7H2O) MW= 246.47 g/mol
Calculate the osmolarity of 1 Liter of solution that contains
40mEq of sodium, 20 mEq of potassium, 60 mEq of chlorine and 5% w/v
of dextrose (mol way: 180 non-electrolyte).
My teacher gave me the answer but I didn't understand how they
got it. thank you.
2. Calculate the osmolarity of 0.5 g/mL of magnesium sulfate heptahydrate - MgSOa.7H20 MW-246.47 g/mol 0.59 Calculate the osmolarity of...
Sodium hydroxide is standardized by a reaction with potassium hydrogen phtalate (KHP, MW 2042 g/mol). Calculate the molarity of a NaOH solution if 0.5123 g KHP were titrated to the equivalence point with 22.75 mL solution of NaOH. 0.0002509 moll Ob 0.02275 moll O c.0.1103 mol/l Od 1.10 mol/l
2 dibenzalacetone acetone benzaldehyde MW- 106.13 g/mol bp-1 78°C d 1.04 g/mL MW 234.30 g/mol mp #110-1110 MW-58.08 g/mol bp 56°C d 0.79 g/mL Its bs Reaction Setup (3 pts) S. OS Initial quantity of NaOH: S. I Initial quantity of benzaldehyde: mL Initial quantity of acetone: mL Theoretical yield of dibenzalacetone based on benzaldehyde: (show calculations) Theoretical yield of dibenzalacetone based on acetone 9 (show calculations) ce tone Limiting Reagent: Product Data (10 pts) fivAL Mass: 3.3g Percent Yield:...
Materials: NaOH MW = 40 g/mL, KHP - potassium hydrogen phthalate, KHC8H404, MW = 204.23 g/mol. Acetic acid, HC2H302, MW = 60.05 g/mol Part 1: Standardization of NaOH Assume 0.951 g of KHP is weighed and transferred to a 250 mL Erlenmeyer flask. Approximately 50 ml water is added to dissolve the KHP. Note that the exact volume of water is not important because you only need to know the exact number of moles of KHP that will react with...
Materials: NaOH MW = 40 g/mL, KHP - potassium hydrogen phthalate, KHC8H404, MW = 204.23 g/mol. Acetic acid, HC2H302, MW = 60.05 g/mol Part 1: Standardization of NaOH Assume 0.951 g of KHP is weighed and transferred to a 250 mL Erlenmeyer flask. Approximately 50 ml water is added to dissolve the KHP. Note that the exact volume of water is not important because you only need to know the exact number of moles of KHP that will react with...
5.8 g of
1,4-di-t-butyl-2,5-dimethoxynezene
(250.37 g/mol) were synthesized by reacting
10.5 mL of t-butyl alcohol (MW 74.12 g/mol, D
0.79 g/mL), 25 mL of concentrated sulfuric
acid (MW 98.08 g/mol, D 1.84
g/mL), and 5.9 g of 1,4-dimethoxybenzene (MW
138.17 g/mol) together. Calculate the percent
yield of this reaction.
Question 1 2 pts 5.8 g of 1,4-di-t-butyl-2,5-dimethoxynezene (250.373/mol) were synthesized by reacting 10.5 mL oft- butyl alcohol (MW 74.12 3/mol. D 0.795/mL), 25 mL of concentrated sulfuric acid (MW 98.08...
8. If the reaction shown was carried out by allowing 7.50 mL of 2,2,3-trimethyl-3-pentano (MW=130.23 g/mol, d 0.857 g/mL) to react with catalytic acid to generate 3,4,4-trimethyl-2-pentene (MW=112.21 g/mol) and water, what is the theoretical yield (in grams) of the alkene product? (15 pts) OH H₂O H3PO4 + 4, 60 min 3,4,4-trimethyl-2-pentene 2,2,3-trimethyl-3-pentano 7. 50mL 15% 857 - 8.75 - 10 150.23 knool 112.215
Calculate the osomolarity of 0.5 g/mL of magnesium sulfate
heltahydrate (MgSO4*7H2O) MW= 246.47 g/mol
Calculate the osmolarity of 1 Liter of solution that contains
40mEq of sodium, 20 mEq of potassium, 60 mEq of chlorine and 5% w/v
of dextrose (mol way: 180 non-electrolyte).
My teacher gave me the answer but I didn't understand how they
got it. thank you.
2. Calculate the osmolarity of 0.5 g/mL of magnesium sulfate heptahydrate - MgSOa.7H20 MW-246.47 g/mol 0.59 Calculate the osmolarity of...
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