How many mL of glycerol (MW=92.1 g/mol, density 1.26 g/mL) must be used to prepare 250.0...

Question

Question

How many mL of glycerol (MW=92.1 g/mol, density 1.26 g/mL) must be used to prepare 250.0 mL of a 0.150 M glycerol solution? Answer: 2.74mL glycerol

science chemistry

Answer 1

Answer #1

Answer 2

Similar Homework Help Questions

How many milliliters of pure liquid methanol (CH3OH, MW = 32.04 g/mol) are needed to prepare...

How many milliliters of pure liquid methanol (CH3OH, MW = 32.04 g/mol) are needed to prepare 250.0 mL of an aqueous solution of 19.0 g/L methanol? The density of pure liquid methanol is 0.791 g/mL. Then, express the methanol concentration as a volume percent (% v/v).
A 5.0067 g sample of Na2CrO4 (MW = 161.97 g/mol) is dissolved in 250.0 mL of...

A 5.0067 g sample of Na2CrO4 (MW = 161.97 g/mol) is dissolved in 250.0 mL of water. Assume the solution has a density of 1.00 g/mL. A 50.0 mL aliquot of the solution is then diluted to a final volume of 250.0 mL. What is the concentration of Na+ in the diluted solution in units of parts per million (ppm)?
You wish to prepare 100.0 mL of a 325.0 ppm w/v sodium (MW = 22.9897 g/mol)...

You wish to prepare 100.0 mL of a 325.0 ppm w/v sodium (MW = 22.9897 g/mol) solution. How many grams of sodium dichromate dihydrate (Na2Cr2O7·2H2O, MW = 297.998 g/mol) are needed to prepare this solution? Assume the final solution has a density of 1.00 g/mL.

How many moles of benzaldehyde (density d = 1.04 g/ml), (molecular weight mw = 106.12 g/mol)...

How many moles of benzaldehyde (density d = 1.04 g/ml), (molecular weight mw = 106.12 g/mol) are required to react with 1.0 ml of acetone: (density d = 0.79 g/ml), (molecular weight mw = 58.08 g/mol)? 6. What is approximate theoretical yield for problem # 5 if you obtained 2.1 grams of dibenzylidene acetone (mw = 234.29 g/mol)?
-Convert 85.0 g/L EDTA (MW=372.20 g/mol) to % (w/v) -Convert 750 mM Glycerol (MW= 92.09 g/mol,...

-Convert 85.0 g/L EDTA (MW=372.20 g/mol) to % (w/v) -Convert 750 mM Glycerol (MW= 92.09 g/mol, Density= 1.25 g/ml) to % (v/v) -Convert 7.25 % (w/v) B-Mercaptoethanol (MW= 78.13 g/mol, Density= 1.1143 g/ml) to mM -Convert 7.25% (w/v) B-mercaptoethanol (MW= 78.13 g/mol, Density= 1.1143 g/ml) to g/L
A concentrated HNO3 (MW = 63.0128 g/mol) solution is 70.0 %wt HNO3 and has a density...

A concentrated HNO3 (MW = 63.0128 g/mol) solution is 70.0 %wt HNO3 and has a density of 1.42 g/mL. How many milliliters of the concentrated HNO3 solution must be diluted to obtain 500.0 mL of 1.00 M HNO3?

A 5.9957 g sample of Na, CrO, (MW = 161.97 g/mol) is dissolved in 1000.0 mL...

A 5.9957 g sample of Na, CrO, (MW = 161.97 g/mol) is dissolved in 1000.0 mL of water. Assume the solution has a density of 1.00 g/mL What is the concentration of Na* (MW = 22.9898 g/mol) in the solution in units of molarity (M)? concentration: М What is the concentration of Na+ in the solution in units of parts per thousand (ppt)? concentration: ppt A 50.0 mL aliquot of the solution is then diluted to a final volume of...
For the reaction below, 11.2 g of triglyceride (MW = 762.0 g/mol) and 52.0 mL of...

For the reaction below, 11.2 g of triglyceride (MW = 762.0 g/mol) and 52.0 mL of 6.0 M NaOH was used. How many mols of base will be left over once the reaction has completed? (Answer to the Ten Thousandths) Reaction: glyceryl tripalmitate + 3 NaOH --> 3 sodium palmitate + glycerol
Glycerol (C3H8O3, 92.1 g/mol) is a nonvolatile nonelectrolyte substance. Consider that you have an aqueous solution...

Glycerol (C3H8O3, 92.1 g/mol) is a nonvolatile nonelectrolyte substance. Consider that you have an aqueous solution that contains 28.8 % glycerol by mass. If the vapor pressure of pure water is 23.8 torr at 25oC, what is the vapor pressure of the solution at 25oC? Enter your answer in units of torr to three significant figures.

You wish to prepare 250.0250.0 mL of a 225.0225.0 ppm w/v Fe2+Fe2+ (MW=55.845 g/molMW=55.845 g/mol) solution....

You wish to prepare 250.0250.0 mL of a 225.0225.0 ppm w/v Fe2+Fe2+ (MW=55.845 g/molMW=55.845 g/mol) solution. How many grams of ferrous ammonium sulfate hexahydrate (Fe(NH4)2(SO4)2⋅6H2O(Fe(NH4)2(SO4)2⋅6H2O, MW=392.14 g/molMW=392.14 g/mol) are needed to prepare this solution? Assume the final solution has a density of 1.00 g/mL.