Question

6. Given the genetic map derived by Hfr minning of a bacteria as shown above, which of the markers could be more finely manned by co-transduction us PL its consid bolds about 2 min of DNA? Circle all that apply. A) his and lac B) lys and unl C bio and the D) all of the markers can be mapped by PI co transduction E) none of the markers can be mapped by PI co-transduction 7. Which of the following types of DNA compaction involves the nuclear matrix? A) Radial loops B) Nucleosomes C) Negative supercoiling D) 30 nm fiber E) Heterochromatinization 8. In the space below, draw the following sequence with an inversion mutation of the boxed region 5'-AGCTCGATCGTOGTGAGCIGTCGA-3 3-TCGAGOIAGCAGCACTCGACAGCT-5 so 9. In which part of a gene could you get a frameshift mutation? A) Regulator binding site B) Promoter C) Terminator D) Structural component E) Any of the above 10. Which of the following is statements about the Griffith transformation experiment with Type Il and Type III S pneumoniae variants is not true? A) Heat killed Type IIIS bacteria do not kill an infected mouse B) The capsule of the heat killed type IIIS bacteria is still intact C) Living Type IIR bacteria do not kill an infected mouse D) A Type II bacterium can mutate into a Type III bacterium as a result of a single mutation E) Heat killed Type IIIS bacteria mixed with living Type IIR bacteria will kill an infected mouse

Answer 1

Answer 6: All of the above marker can be mapped by PI co transduction

Answer 7: Radial loops

Source: Specific DNA sequences associated with the nuclear matrix in synchronized mouse 3T3 cells, Proc. Nati. Acad. Sci. USA Vol. 80, pp. 6887-6891, November 1983

Answer 8:

5'-AGCTCGATCGTCGTGAGCTGTCGA-3' 3'-TCGAGCTAGCAGCACTCCACAGCT-5' Inverse mutation Inverse mutation 5'-AGCTCGCGAGTGCTGCTATGTCGA-3' 3'-TCGAGCGCTCACGACGATACAGCT-5’

Answer 9: Any of the above

Answer 10: Option ‘B’ is not true