Question

have the disease lods ISUUT. In a group of Learning Store students, 32% could roll their tongues, a trait determined by a dominant allele. The other 68% of the student population were non-rollers. Calculate the frequencies of the dominant and recessive alleles in this student population. 0²= 32 = 0.32 ptq=1 P 100 The frequency of the dominant alleles is 0, 6 and the frequency of the recessive alleles in this student population is 0.4. 0.679=1 g=1-0.6-0.4 q=0.4 p=10.32 p=0.6 FUNG

Answer 1

Let, P-frequency of dominant allele 9 - Frequeney of necessire allele. p? = frequency of homozygous dominant individuals 2p9 = frequency of heterozygous individuals q2 = 'frequency of homozygous recessioni viduals According to Hardy-Weinbeog, prq=1 and p²+2pq +9 = 1 In this giren problem, 32% could poll their tongues, a trait determined by a dominant allele. The other 68% of the student population were non pollers. i q2 = 68% -680 = 0.68 and p2+2p9 = 32% as non rollars have only alloles homozygous recessione alleles] as homozygous minant q = 0.68 ; q = 70.68 = 0.825 .. p = 1-0.825 - 0'175 P = (0:175)2 = 0.031 209 = 0.289 pi+2pq = 0°39 = 32% Therefore, the [ Giren above] frequency of dominant allele in this student population * (P) = 0'175. and the frequency of recessive allele in this student population (2) = 0.895. land heterozygous individuals have dominant phenotype]