Answer: A female with straight legs whose father was bent legged will be heterozygous for straight legs
Let the allele for straight legs be expressed as XS
Allele for bent legs be Xs
The female is heterozygous hence her genotype will be XSXs
Let the genotype of straight legged male be XSY
Note:The gene for straight leg is on X chromosome and male gets only one X chromosome, so if the male is expressing the dominant character of the straight leg then he will have only one allele XS for the character.
Male will express the recessive character of bent leg even if he has only one allele for bent leg Xs since he is not having another X chromosome. The character of bent legged will be expressed in males mostly than the females.
If the heterozygous straight legged female is crossed with straight legged male then the cross would be as follows
|
gamates |
XS |
Xs |
|
XS |
XSXS Straight legged female |
XSXs Straight legged female |
|
Y |
XSY Straight legged male |
XsY Bent legged male |
The phenotypic ration will be 3:1 i.e. three straight legged and one bent legged.
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