
En (mv) [] in mM 150 Inside Outside neuron neuron 10 12 120 100 1.25 250...
9. Voltage clamps are normally used to “clamp” or “freeze”
membrane potential at a particular value and then measure the
resulting ionic currents. Explain how setting a voltage clamp at
the presynaptic terminal to a very positive potential can prevent
synaptic transmission (hint: synaptic transmission is triggered
using voltage-gated Ca++ channels, and you can assume typical Ca
concentrations inside and outside the cell from the table.
Please explain how setting a voltage clamp at the presynaptic
terminal to a very...
Questions: 1. Nerves: Get your calculators out! As expected, you are about to experience the deep satisfaction of solving the Goldman equation to predict the axon membrane potential, as presented in your book and lecture notes. Nernst (cations only): V (MV) = 61 log(CIC) P Na+PK)-PaC). Goldman: V (mV) = 61 log P [Na]. + P (K). + PCI)- To solve this equation, you will need to use the following concentrations inside (i) and outside (o) the cell and permeabilities...
12. At equilibrium the Na+ concentrations are 100 mM outside and 10 mM inside the cell, what is the voltage difference across the membrane?
(30%) 2. A hollow circular steel member with outside and inside diameters 150 mm and 120 mm and wall thickness 15 mm functions as a pin-ended column 4 m long. Determine the maximum load the column can carry if the load has a known eccentricity of 20 mm, as shown in Fig. 2. Use the allowable stress method and let E = 200 GPa and o, = 250 MPa 20 mm
please
answer 18.11 and 18.12
18.11 A steel ring with an outside diameter of 150 mm and an inside diameter of 100 mm is shrunk onto another steel ring with an inside diameter of 50 mm. An axial force of 56,54 kN is needed to push the rings apart. Calculate the pressure at the mating surface and the shrinkage allowance given that both rings are 20 mm thick and the coefficient of friction between the mating surfaces is 0,2. Using...
*** I need help with PART F of
this problem. Hints are given in other parts of the problem and all
information available is given on the worksheet. Please help, thank
you!
The post-synaptic cell at a chemical synapse has the following distribution of ions between the cytosol and the extracellular environment. Consider that the relative permeabilities for Na, K and Cl' are 1, 100 and 50, and that there are no other significant permeabilities, lon Concentration (in mM) Extracellular...
***I need help on PART E of
this problem. All of the information is given on the worksheet
along with the hints on each part. Thank you!
The post-synaptic cell at a chemical synapse has the following distribution of ions between the cytosol and the extracellular environment. Consider that the relative permeabilities for Na, K and Cl' are 1, 100 and 50, and that there are no other significant permeabilities, lon Concentration (in mM) Extracellular Equilibrium potential mV) Intracellular 146...
You are studying neurons in the lab by growing them in culture (in a petri dish outside the body). You grow them in an incubator at 37 degrees C. With this experimental setup, you can easily change the extracellular ion concentrations by switching the cell culture medium (the fluid that surrounds the cells).Intracellular concentrationMedium 1 (extracellular concentration)Medium 2 (extracellular concentration)K+140 mM4.5 mM50 mMNa+10 mM135 mM100 mMCl-12 mM125 mM120 mMa.If you switch from Medium 1 to Medium 2, will the intracellular...
SHOW YOUR WORK, PLEASE WRITE LEDGIBLY AND CLEARLY 1. Patch clamp recording of a single ion channel yields the following results: Holding Potential Measured Current (mV) 100 50 (pA) 1.0 0.0 +50 +100 +2.0 +3.0 A) Draw a graph of the current (on the vertical axis)-voltage relation for this channel. B) What is the electrical resistance (in ohms) of this channel? (keep in mind mVa 103 volts, pA 101 amperes, and an ohm is a derived unit that is equivalent...
can
someone help with #2
150 mL of 10-1-(WA) SDS 1w/veg of solute/100 ml 10g: 100 ml 150 ml 10g) 15g SDS in 150 ml dd Haa (100ml) b. 200 mL of 250mm tris buffer, por 7.5 Tris 1210 g/mol PH 7.5 es pot - 14-7.5 = 6.5 Pka of tris: 205 -> pkb - 14-pka = 5.94 POH pkb + log [ BH"] Balt [B]-* [et] Tel : antilog (6.5-5.94) - 3.631 [4] . 3.631 [8] [BHT] + [b],...