Question

The data bele w represents the data The data below represents the data recorded after the hydrolysis of a substrate by an enzyme. [S]/10-4 M 2.1 4.2 9.3 14.2 vo / 10-6 M. 1.2 3.1 6.3 min-1 9.1 Calculate Vmax, Km and K2 using a Lineweaver-Burk plot. Assume Michaelis. Given [E}o is 5.0 X 10-6 M

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Answer 1

This information is enough to solve the problem. Actually, we first need to plot a graph from the given values.

We know, the Lineweaver-Burk plot is a plot of "1/[S] vs 1/v0". We will calculate these and plot it in the graph with

1. 1/[S] on X-axis
2. 1/v0 on Y-axis.

From this graph, we can calculate Vmax, Km, and K2.

(1/[S])/10-3 M-1	(1/vo )/10-5 M-1 · min
4.8	8.3
2.4	3.2
1.1	1.6
0.7	1.1

Below is attached the Line-Beaver Burk plot from the values in the table above.

. (1/vo/10-5 M-1-min (1/[S])/10-3 M-1 1.5 34.5 (1/vo)/10-5 M-1 - min

The linear equation for this graph:

y = 176x + 4.23 X 104; we compare this with the standard equation of a straight line, i.e. y = mx + c, where 'm' is the Slope of the graph, and 'c' is the Intercept.

Vmax is solved by the following quation:

Intercept = 1/Vmax
Vmax = 1/(4.23 X 104)
Vmax = 2.36 X 10-5

Km is solved as:

Slope = Km / Vmax
Km = Slope X Vmax = (176) X ( 2.36 X 10-5)
Km = 4.2 X 10-5

To solve for K2, we use:

K2 = Vmax / [E}0
K2 = (2.36 X 10-5) / (5.0 X 10-6 M)
K2 = 4.72 min-1

Hope the quation is clear now. Have a nice day.