Question

Question 1 2 pts How does a noncompetitive inhibitor decrease the rate of an enzyme-catalyzed reaction? by decreasing the free-energy change of the reaction catalyzed by the enzyme by binding to an allosteric site, thus changing the shape of the active site of the enzyme by binding to the active site of the enzyme, thus preventing binding of the normal substrate by binding to the substrate, thus changing its shape so that it no longer binds to the active site of the enzyme Question 2 2 pts Which of the following processes would be most directly affected if a thylakoid membrane is punctured so that the interior of the thylakoid is no longer separated from the stroma? flow of electrons from photosystem II to photosystem! splitting of water synthesis of ATP reduction of NADP+

Answer 1

1) 3rd option is correct non reversible Inhibitor binds to allosteric site of enzyme and thus changing the shape of active site of enzyme and hence no substrate binds

2) 3rd option is correct ATP synthesis will be affected

As puncturing of thylakoid membrane cause leakage of H+from lumen to stroma so no gradient formed so no ATP synthesis take place.

3) option 2 is corect ,O2 release is process of light reaction

As PSII cause breakdown of water and leads to release of H+ and O2 and electron towards lumen of thylakoid membrane

4) option 2 is correct as ATP which is synthesized from cetabplic reaction is used for several important cellular processes.

Like glucose oxidized by glycolysis process which release ATP which is used for several cellular process like working, breathing , metabolic processes.

Hope it's clear..thanks