3.You’re interested in the genetic basis for autism spectrum disorders (ASD). To model and understand this condition, you perform genetic screens in the zebrafish Danio rerio in order to find mutations that mimic aspects of human autism phenotypes. Your screen identifies a series of 6 true-breeding mutants that have autism-like symptoms in zebrafish (and name these autism mutants aut-1 through aut-6). You cross together each of these mutants and examine their progeny (the F1 generation) and note their phenotypes in the table below. (A is autism phenotype, N is normal wild-type zebrafish behavior, and the row and column names indicate which combination of mutants were crossed together in each case). PLEASE SHOW ALL WORK AS DETAILED AS POSSIBLE!!
aut-1 aut-2 aut-3 aut-4 aut-5 aut-6
aut-1 A N N N N N
aut-2 N A N A N N
aut-3 N N A N N N
aut-4 N A N A N N
aut-5 N N N N A A
aut-6 N N N N A A
When two similar looking mutants are
allowed to cross and the resulting F1 progeny exhibits the WT
phenotype, it shows that both the mutations are located at
different loci. i.e. they are non-allelic.
When two similar looking mutants are allowed to cross and the
resulting F1 progeny exhibits the mutant phenotype, it means that
both the mutations are located at the same locus i.e. they are
allelic to each other.
In the given case,
N = WT phenotype
A = Mutant phenotype
Complementation groups:
1. aut-1
2. aut-2 and aut-4
3. aut-3
4. aut-5 and aut-6
There are four different loci are
mutated in the given set of mutants.
All the given mutants are recessive as any of the F1 progeny do not
exhibit 100% phenotype.
3.You’re interested in the genetic basis for autism spectrum disorders (ASD). To model and understand this...
You are interested in mouse eye development and conduct a genetic screen for mutations that result in strong eye defects. After treating a male mouse with ENU (a chemical mutagen that induces base-pair changes and small deletions), you identify four mouse mutants 1-4, each with defective eyes. You cross each of the four mutant mice with eye defects to homozygous wild type mice and examine the progeny from each cross. What type of information can you get from observing the...
please show all work.
2. To understand the genetic basis of locomotion in the diploid nematode Caenorhabditis elegans, recessive mutations were obtained, all making the worm "twitch" ineffectually instead of moving with its usual smooth gliding motion. These mutations presumably affect the nervous or muscle systems. Twelve homozygous mutants were intercrossed, and the hybrids were examined to see if they twitched or not. The results were as follows, where "" means that the hybrid was wild type (gliding) and "t"...
6. Drosophila have antennae on their heads. Two mutants with abnormal antennae were obtained in a mutant hunt. After establishing true breeding strains of the mutants, Sally did the following crosses. Draw conclusions from her results. Suggestion: where helpful, outline the cross as a Mendelian set-up, choose letters. a. ant 1 X wild type, produced all flies with normal antennae. (2 pts) b. ant 2 X wild type produced all flies with normal antennae. (2 pts) Next Sally crossed the...
Biol 210: Genetics. Assign. #1 #5) You are studying a gene for body colour in house flies. The wild-type allele (B) has a dark blue phenotype. In population screens you find 6 recessive mutants B' through B$ and establish homozygous strains, all of which have a pale blue phenotype. You cross each mutant strain to itself and to all the other mutant and wild type lines and observe the following results (+ = wild- type phenotype in F1, -= mutant...
ing genetic map: 2. 3 > chromosome 3: 5 N. 35 me chromosome 7: >0 20 mu <a 15E ASR 7 8 9 10 Questions 1-6 are to be answered in order in the respective boxes below. Final answers must be entered online. (Your answer should be a number between 0 and 100 to two decimal places for example, one number as a final answer including or between "0.00" through "100.00"). Round to the nearest hundredths and do not include...
Fun-filled Genetics activity Set Psa plants were particularly well suited for use in Mendel's breeding experiments for all of the following m e thal Al was show easily terved various in a number of characters, such as a shape and flower color, it is powible to completely control tingshotween different pe plants, it is possible to a large numbers of progeny from any given cross. Dipeas have unusually long generation time, many of the observable characters that vary in pea...
Bio215 Problem Questions Hassanaton MULTIPLE CHOICE 1) Pea plants were particularly well suited for use in Mendel's breeding experiments for all of the following reasons exep that ) peas show easily observed variations in a number of characters, such as pea shape and flower color. B) it is possible to completely control matings between different per plants. C) it is possible to obtain large numbers of progeny from any given cross. D) peas have an unusually long generation time. E)...
2. A dominant allele H reduces the number of body bristles that Drosophila flies have, giving rise to a “hairless” phenotype. In the homozygous condition, H is lethal. An independently assorting dominant allele S has no effect on bristle number except in the presence of H, in which case a single dose of S suppresses the hairless phenotype, thus restoring the "hairy" phenotype. However, S also is lethal in the homozygous (S/S) condition. What ratio of hairy to hairless flies...