Homework Answers
2H2 + O2 ---> 2H2O
change in moles delta(n) = 2 - 3 = -1
T = 25 oC = 25 + 273 = 298 K
R = 8.314 J/K.mol
Feed values,
maximum work done = -delta(n)RT = -(-1) x 8.314 x 298 = 2.48 kJ
Change in entropy deltaS = -nRlnX
X being the mole fraction of H2 or O2
mole fraction of H2 = 2/3 = 0.67
mole fraction of O2 = 1/3 = 0.33
deltaS = -(2 x 8.314)ln0.67 - (1 x 8.314)ln0.33
= 6.66 + 9.22
= 15.88 J/K
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