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Compute the maximum acceptable tensile service load that may act on a single angle L6x4x3/4 that is welded along its 6 leg t
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47 Yield Strength of grow area L 6x4x 314 Ag = 6.94 in? ă = loot in & Pn = 0.9% FY x Ag 0.9 * 36 * 6.94 (OPn 22 dp 86 K 27 RuPn = 224,86 k 3} Calculate service load P. = 3 Po Pu= 1.2 Pp + 1.6 Pr 1.2 Po t 1.6 (30) 24.86 6 Po 37.48k service Dead load P

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