Assume all temperatures to be exact.
A 0.25-kg glass cup at 27?C is filled with 0.43kgof hot water at
81?C. Neglecting any heat losses to the environment,
what is the equilibrium temperature of the water? C { the specific
heat of glass is 840 j/kg/.c}
Note that
Qglass + Qwater = 0
Thus,
mglass cglass (Tf - 27) + mwater cwater (Tf - 81) = 0
Solving for Tf,
Tf = 75.36 degrees C [ANSWER]
Assume all temperatures to be exact. A 0.25-kg glass cup at 27?C is filled with 0.43kgof...
6. A 0.500kg glass (c=840 J/kg°C) containing 1.00L of water (at 20.0°C) is filled with 0.100kg of ice (initially at -5.0°C). a. What is the mass of the liquid water initially in the glass? b. What is the equilibrium temperature of the water and glass when all of the ice has melted? Ignore any heat gained from or lost to the surroundings. C. A person then drinks all of the water in the glass. How much heat is gained by...
Any
formulas Shown along with work would be greatly appreciated!
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