Question

Then tension in chain A is 340.0 N, and it makes a 65.0 degree angle with its supporting building. Chain B is suspended from a pole, making a 25.0 degree angle with the pole. a. Draw a force diagram b. Determine the tension in chain B. c. what is the weight of the hanging object?

Answer 1

Part a)

First the Diagram of chains on how they are connected and the object is hanging.

A at 65 deg to support building and B at 25 deg and Object hanging vertically. The angless determined are in figure.

CHAIN A 650 CHAIN B 340 N

This must be solved via Lamis Theorem which applicable for 3 coplanar forces, concurrent forces for object in equiibrium states that

FA - FB - Fc sin a sin siny

Here Fa=340 N , Fb=?,Fc=?

a = 155', 8 = 115', 7 = 90%

340 sin 155 FB sin 115 FC sin 90

Part b)

Force/Tension in Chain B, Fb

340 FB sin 155 (sin115) sin 13

FB = 729.13 N

Part c)

Weight of Hanging Object Fc,

340 C sin 16. (sin 90)

Fc = 804.5 N

Surely you understood the concept of lamis theorem and the solution give a like and thumbs up in that case :-D.