Question

Find the answer based on the figure, (a) Determine the equilibrium charge on the capacitor in the circuit of Figure as a (5 points) (5 points) (c) Can the charge on the capacitor be zero? If so, for what value of R? (5 points) (d) What is the maximum possible magnitude of the charge on the capacitor? For (5 points) (e) Is it experimentally meaningful to take R-oo? Explain your answer. If so, what (5 points) function of R. (b) Evaluate the charge when R 20.0 2 what value of R is it achieved? charge magnitude does it imply 3.00 Ω 2.00 2 3.00 uF 5.00 V 80.0 Ω

Answer 1

Using concept of voltage division voltage of left side = (80/80 + 3)^5 = 4.82 V voltage on rightside = (R)/(R + 2) 5 Suppose right side is at (+) terminal, Voltage the capacitor = 5R/R + 2 - 5 times 80/83 = 5 [R/R + 2 - 80/83] = 5 (R/R + 2 - 0.96) because Q = CV because C = 3 mu F = 15 times 10^-6 [R/R + 2 - 0.96] when R = 20 ohm Q = 15 times 10^-6 [20/22 - 0.96] = 19.7 times 10^-6 C = 19.7 mu C Charge on capacitor will be zero when = > 0 = 15 (R/R + 2 - 0.96) = > 15 R/R + 2 = 15 times 0.96 = > 15 R = (R + 2) 4.8 0.2 R = 4.8 times 2 R = 48 ohm Maximum value of charge when R = 0, Substituting we get Q = 15 times 10^-6 (0 - 0.96) = -14.4 mu C \r\n It is experimentally
please upvote if it helps