Question

A coll of 55 turns is wrapped around a long solenoid of cross-sectional area 5.5 x 10"m". The solenoid is 0.40 m long and has 350 turns. (a) What is the mutual inductance of this system (In H)? (b) The outer coll is replaced by a coil of 55 turns whose radius is three times that of the solenoid. What is the mutual inductance of this configuration (in H)?

Answer 1

Since mutual inductance depends on magnetic foeld of inner solenoid and area of outer solenoid so, Mutual inductance for part A will be 3.3 × 10^-4 Henry, and for part b, it will be 2.99× 10^-3 Henry.

The magnetic flees through each turn of the outer coll due to solenoid es MON, 21 A MONII uniform magnetic field inside the this mutual inductance o ence eo : Where Ho = arx107 Hlm . So, a) Mutual inductance im of the system will be Mo (Gr x103) 350X55 x 5.5X103, = 0.33 MH . 0.40 b) dle an e оtе сол юі # be. teless istə raccount for calculating mutual incluctance dBo, Aree! ^- rv2, S0, A, 2(377) TagAL SP, M3 (43x167) / 3.50455 ) x 5.5 x 98-109 . = 2.99 mH