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Earth's magnetic field at the equator is directed horizontally from south to north and has a...

Earth's magnetic field at the equator is directed horizontally from south to north and has a strength of 0.310 gauss. Suppose copper wire with mass of 12g and length of 10m could be placed in the B-field without support. Determine the magnitude and direction of the minimum current required in the wire so it just floats above the surface of the Earth. (1 gauss= 10^-4T)

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Answer #1

T B = 0.310 gauss - 0.310x10 w=128 = 0.012 kg = 10 m ng Current Ir Bi I = 0.012 kg x 9.8 m/s2 0.310x10 Tx 10 m I- 3 79.35 A.

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