Question

16. Two forces F, and F2 act on the 8.5kg block shown in the drawing below in addition to the normal force and gravity. The magnitudes of the forces are F1-55N and F2 = 20N which is the friction. a. Use the blank x,y graph to the right below to depict all of the forces acting on the block. Hint: Draw all of the forces originating from the origin, and be assured that the object will not travel downward through the floor. E 100 8.5kg b. Write an equation for the sum of the horizontal forces acting on the block (meaning in the x-direction) c. Write an equation for the sum of the vertical forces acting on the block (meaning in the y-direction). d. How much does the block weigh?

Answer 1

@ 27 40° X F2 ak w 6 ma Along the x direction net force is [ Ex= F cos 40°- Fz = 55 cos 40°- 20 ( and we get a= 2.6 m/s) Along direction, net force is OY 8 sa © s Fy: N- W Fsin 40° -0 N- mg - Sin 4o* : 0 we N From © can write Na mg + F, sin 40° - (8-5 X 9.8)+ 55 sin 40° 118.65 So, even though the block has 859: 83.3 M, for a weighing floor, it's apparent 118 6 5 N an actual weight of balance kept kept on cwill be shown weight