Question

A uniform electric field collapses to zero from an initial strength of 0.6 MV/m in a time 15 µs in the manner shown in Figure. 3. What is the displacement current in Amperes through a 2.9 m2 region perpendicular to the field during the time interval (a)?

0.6 (a) 04 (NV/m) 0.2 0 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 (8) Figwe 3 14 - A uniform electric field collapses to zero from an initial strength of 0.6 MV/m in a time 15 us in the manner shown in Figure. 3. What is the displacement current in Amperes through a 2.9 m² region perpendicular to the field during the time interval (a)? 4.4 2.6 1.3 5.2 1.9

Answer 1

14 1.3 Amberes, Displacement current is giren by ID = (s. ) 8.85 A area to the 6. = Permittivity of medium. (here, 10-12) Orthogonal field (2.9 m²) field gradiant (Need to find from the graph) 110,6-0) wym at 0.6 la) 0.4 I 2 3 4 2 4us az 4 X 10-6 -12 = 0.05X10 Yms Now, put the for interval (a) Values to find ID- ID x 2.980.0581043) 1.3 A { rounded toone, decimal bloce} which is the required displacement current. The third option is correct. 8.85 X20-12