Question

In the production of vinegar, the fermentation of ethanol to produce acetic acid using acetic acid bacteria can be simplified by the following reaction

     Ethanol (A) +   bacteria cells à more bacteria cells (C) + acetic acid (R)

The data below shows the concentration of ethanol from a 2 l MFR reactor at 50 ⁰C.

(c_co = 0 mg/l and fractional yield R/A = 0.25)

Table 3: Experimental data

ν (l/hr)	Cethanol (mg/l)
0.2	5
0.55	20
0.86	60
1.0	150

1. Show that the data fits substrate-limited Monod kinetics. Find the k and C_M values and state their unit. Please use the graph paper provided.

2. The fermentation is then to be performed in a large MFR. Determine the size of the reactor needed to convert 90 % of 7 l/hr of ethanol with an inlet concentration of 200 mg/l and calculate the exit acetic acid concentration. (There is no cells entering the reactor( c_co = 0) and R/A = 0.25)

3. Is the MFR in (b) operated at an optimum condition? Support your answer with the appropriate calculations. If the operation is not optimum, how much flow need to be by-passed to operate at optimum?

Answer 1

we know H 't follows monal to uster we 나 M и U=D D-v VOL. Data we hove. SAO Sol From monod kinectics that - ИСА. CMICA To determine whether Kinches find Plot blano См. I uc Line Comes If Straight thon model is followed state At steady Obtining A plotting R=0.99 y = 24188744106419 Model is followed toia Cm=0.609 X4 1.687= 1850389 mg/l 3. now too foo Vo = 74.hu X=0.9. Cao = Joomg/L. Coco. Balonce on Elhonol VoCo - voln - M G V =o. Cro-CAM CA T. Croten CA = Cno (1-0.6)= Joox 0.1= 90 mg/L. k=0-609 hil = 1-6419 Too

200-20-0-609x600) T. 26-309+(90) 100 5-366 7 T= 33.530 V-33-53047-1234-77 L CR=0.95x(Cno-CA) CR-0-98X100 - 145 mg/L ③. At optimum Dopt = 0.609 Conditions. Dopt *(1-C KM Cat C Ś 1352385 25-3091900 -0.609 |-0-335] 500609 (0.664) -10.404 hil D = 7. From ooogoo 234.77 for D=Dop- V 234.77 V=234.77X0-404-194.84 Yh - Regwiel Flow

using given data and balance on MFR we can find the required variables

for any doubts write in comments