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A wheel has an angular acceleration given by the equation below: 5t^2 + 3 If the...

A wheel has an angular acceleration given by the equation below: 5t^2 + 3 If the wheel starts at rest, what is the angular displacement between t=3 and 8 seconds?

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Answer #1

Angular velocity w = integral alpha dt = integral 5t^2+3 dt

w = 5t^3/3 + 3t

angular displacement theta = integral w dt

= integral 5t^3/3 + 3t dt

= 5t^4/12+ 3t^2/2

angular displacement between given time = [5*8^4/12+ 3*8^2/2 ] - [5*3^4/12+ 3*3^2/2 ]

= 1755 rad answer

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