The code wil be
module factor (N, z);
input [2:0] N;
output [15:0] z;
reg [15:0] z;
integer i;
always @ (N)
begin
z = 1;
i = 0;
for(i=1;i<=N;i = i + 1)
Z = i* z;
end
endmodule
module test;
wire (15:0]z;
reg (2:0]N;
factor f(N,z);
initial
$monitor("fact (%d) = %d",N,z);
initial
begin
#0 N=7;
#5 N=6;
#5 N=5;
#5 N=4;
#5 N=3;
#5 N=2;
#5 N=1:
end
endmodule
The output

please explain Question 3 1. Write behavioral Verilog code to calculate the factorial of a 3-bit...
write 3-bit Gray code using jk-flip flop in verilog (behavioral code)
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1) Using Verilog behavioral modeling, describe an n-bit circuit that has four n-bit unsigned inputs A B, C, and D, and two control inputs C1, and CO. The circuit produces an n+1-bit output Y according to the following table: (No delavs) 120 marks CI CO Function 1 Y MAX (A,B,C,D) , i.e. Y equals the maximum of the four inputs 0 | Y 〈 MIN (A,B,C,D), i.e. Y, equals the minimum of the four inputs 1 YAVERAGE (A,B.C,D), i.e. Y...
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please give the verilog code and explain in the form
of comments.
Part I Consider the circuit in Figure 1. It is a 4-bit synchronous counter (text Section 5.9.2) that uses four T-type flip- flops (text Section 5.5). The counter increments its value on each positive edge of the clock if the Enable signal is asserted. The counter is reset to 0 by setting the Clear b signal low - it is an active-low asynchronous clear. You are to implement...
Please code the following in Verilog:
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