Question

2. A 0.4682 g sample of a metal is dissolved in a total volume of 50.0 mL. a. If the metal was pure silver, how many mL of a 0.1215 M KSCN solution would be required to react with a 5.00 mL aliquot of the alloy solution? b. If the metal was pure copper, what would be the absorbance of the solution?

Answer 1

The answer of the 2 nd question's a part is given below;

289) We know that malarity no cef moles of solule Civen that Volume (L) mass of sample : 0.4682 g molar muss of Ag 108 g/mol na mass 0,4699 Mim To8 0.00433 = 0.0867M 0:05 Given that M₂ = 0.1215M 0.00433 mol So, white ritirting : Tag M,VT MV2 mivi Vi śmi to,=0.0867 Vz? M2 Vr = 0.0867 mx 5 ml 3.568mL 0-1215 M Hence 3.568ml vot. of KSCN required