Question

After being accelerated to a speed of 1.35×10⁵ m/s , the particle enters a uniform magnetic field of strength 0.900 T and travels in a circle of radius 30.0 cm (determined by observing where it hits the screen as shown in the figure). The results of this experiment allow one to find m/q.

Find the ratio m/q for this particle.

Answer 1

Since the particle is doing the circular motion due to the magnetic field.

mv²/r=Bqv

where m is the mass ,v is the velocity,r is the radius of the circle, B is the magnetic field,q is the charge and v is the velocity.

now if we simplify this equation we get

m/q=Br/v

B=0.9, r=30 cm=0.3 m, v=1.35* 10⁵

m/q=(0.9 * 0.3)/(1.35* 10⁵)

m/q=0.27/(1.35* 10⁵)

m/q= 0.2 * 10^-5 Kg/C

All the best !!!

Answer 2

SOLUTION :

Particle moves in a circle of radius, r = 30 cm = 0.3 m

Magnetic field , B = 900 T = 0.9 kT 

Speed of particle, v = 1.35 * 10^5 m/s

Charge = q 

mass of particle = m 

Centrifugal force on particle = Magnetic field force on the particle

=> m v^2 / r = B q  v 

=> m/q 

= B r / v 

= 0.9 * (0.3) / (1.35 * 10^5)

= 2.0 * 10^(-6)   kg / C  (ANSWER)