In a laboratory experiment the length of a steel bar alpha= 12x10^-6 1/C is found to be 500 mm when the temperature is 68F. Find the temperature at which the length of the bar is 50.53cm?
Please list all formulas and steps clearly
change in length = original length * alpha* change in temperature
(50.53 - 50) *10^-2 = 50 * 12*10^-6 *( T - 68)
T = 76.83 F
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