A proton of mass 1.67*10^-27 kg is accelerated by a field of 600 N/C. How fast...
A proton of mass 1.67*10^-27 kg is accelerated by a field of 600 N/C. How fast in m/s is it travelling after 20 nanoseconds if it has a charge of 1.60*10^-19 C?
Homework Answers
electric force on proton, F = q*E
m*a = q*E
a = q*E/m
= 1.6*10^-19*600/(1.67*10^-27)
= 5.75*10^10 m/s^2
Apply, v = u + a*t
= 0 + 5.75*10^10*20*10^-9
= 1.15*10^3 m/s
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A proton of mass 1.67*10^-27 kg is accelerated by a field of 600
N/C. How fast...
A proton of mass m_p = 1.67 \times 10^{-27}~kgm p =1.67×10 −27 kg and...
A proton of mass m_p = 1.67 \times 10^{-27}~kgm p =1.67×10 −27 kg and a charge of q_p = 1.60 \times 10^{-19} ~Cq p =1.60×10 −19 C is moving through vacuum at a constant velocity of 10,000 ~m/s10,000 m/s directly to the east when it enters a region of uniform electric field that points to the south with a magnitude of | \vec{E} | = ∣ E ⃗ ∣=2.60e+3~N/C N/C . The region of uniform...
A proton of mass m_p = 1.67 \times 10^{-27}~kgm p =1.67×10 −27 kg and...
A proton of mass m_p = 1.67 \times 10^{-27}~kgm p =1.67×10 −27 kg and a charge of q_p = 1.60 \times 10^{-19} ~Cq p =1.60×10 −19 C is moving through vacuum at a constant velocity of 10,000 ~m/s10,000 m/s directly to the east when it enters a region of uniform electric field that points to the south with a magnitude of | \vec{E} | = ∣ E ⃗ ∣=2.35e+3~N/C N/C . The region of uniform...
A proton of mass m = 1.67 x 10-27 kg and charge q = 1.60 x 10-19 C is accelerated from rest through a potential difference of 4000 V. What final velocity does it achieve? A proton of mass...
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A proton of mass mp= 1.67×10−27 kg and a charge of qp= 1.60×10−19 C is moving...
A proton of mass mp= 1.67×10−27 kg and a charge of qp= 1.60×10−19 C is moving through vacuum at a constant velocity of 10,000 m/s directly to the east when it enters a region of uniform electric field that points to the south with a magnitude of E =3.62e+3 N/C . The region of uniform electric field is 5 mm wide in the east-west direction. How far (in meters) will the proton have been deflected towards the south by the...
PLS ANSWER THIS ASAP I WILL RATE proton (mass 1.67*10^ ^ -27 , charge ^-19 C)...
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particle electron: proton: charge mass me = 9.11 × 10-31 kg me = 1.67 × 10-27 kg m, = 1.67 × 10-27 kg 9e =-1.60 × 10-19 C = +1.60 × 10-19 C neutron: Coulomb's law: F = kelellel/r2 where ke = 8.9875 × 10" N m?/C". Electric field: E = F/go- Electric field of a point charge: E kell/r2. 1. Sketch the electric field of a pair of oppositely charged particles.
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