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A proton (mass m = 1.67 × 10-27 kg) is being accelerated along a straight line...

A proton (mass m = 1.67 × 10-27 kg) is being accelerated along a straight line at 7.30 × 1011 m/s2 in a machine. If the proton has an initial speed of 1.10 × 105 m/s and travels 2.50 cm, what then is (a) its speed and (b) the increase in its kinetic energy?

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Answer #1

a)Let the speed is v.

The initial speed u=1.10105 m/s.

Acceleration a=7.301011 m/s2.

Distance covered is s=2.50 cm =0.025 m.

We know for final velocity

  

  

The speed is 220454.0769 m/s.

b) Let the increase in its kinetic energy is .

  

  

Increasing in its kinetic energy is 3.04810-17 Joule.

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