Wavelength of the light \(\lambda=640 \mathrm{~nm}\)
The angle between the first bright fringes on either side of the central maximum is \(2 \theta=33^{\circ}\)
The angle between the first bright fringes from one side of the central maximum is \(\theta=16.5^{\circ}\)
The condition for the maximum in the diffraction pattern is
\(D \sin \theta=\left(m+\frac{1}{2}\right) \lambda\)
Here, \( m=1\)
$$ \begin{aligned} \text { so } D &=\frac{3 \mathrm{z}}{2 \sin \theta} \quad \text { Where } m=1 \\ &=\frac{3\left(640 \times 10^{-\circ}\right)}{2 \sin 16.5^{2}} \mathrm{~m} \\ &=3.38 \times 10^{-6} \mathrm{~m} \\ &=3.38 \mu \mathrm{m} \end{aligned} $$
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