Question

2. A newly developed region of the planet is isolated and not able to tie in to any existing power system distribution networks. It is decided that the facilities will utilize a five-phase system. Determine the magnitude relationship between the line-to-line and line-to-neutral voltage phasors of a five-phase source. Recall that the corresponding relationship for a standard three-phase network is VL1 = /3Vzx: (5 points)

Answer 1

For - n (phase) > 2 voltage phasees seperated by (360) → voltage level seperated by 360 = 72 n / Phase voltages Va = ph Co + = + 2-3° V = Vph <-144 vd = Uph K-216° Ue = Von <-2880 Line voltages > Vab = Vph <0 - Vph <-720 1 = Vph (120 – 12-72°) - |-1756 2540 IT Vape) = 101956] Vac a Vph Vph <-144° = Vph (2400- 1 (-144°) = Vph (220 - 16-144) vac = 1.9021 Zigo I Vacl = 1.9021

dine voltage for adjacent phases has amplitude 1 1756 Vph and leads voltage by 54° The line voltage for non - adjacent phasen has amplitude 1.902 uph and leads to the phare voltage by 18. for adjacent phases s 1.1756 Uph I 1.902 Vpn for non adjacent phases