Question

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Nite Gas Laws Problem Set 1. According to Dalton's Law, what is the pressure of H, gas in a mixture with a total pressure of 1.5 atm if the hydrogen gas has a mole fraction of 0.5? (Ans: 0.75 atm) 2. In Charles Law the relationship between (P&T or V&T) is determined to be (inversely/directly) proportional. 3. Why must only SI units be used when making calculations using the Ideal Gas Equation? 4. What is the molecular mass of a gas with a density of 1.34 g/L at STP? (Ans: 30 g/mol) 5. At 30 degrees Celsius, a gas is found to have a volume of 1.2 L at a pressure of 235 Torts. If the Molar Mass of the gas is 98 g/mol, then what is the density of the gas? (Ans: 1.2 g/L) 6. Calculate the equivalent of 856 tons in atm. (Ans: 1.12 atm) 7. The pressure (increases/decreases) when the volume changes from 2.5L to 13L 8. A sample of gas has a volume of 252mL at a pressure of 641 torr. What volume, in mL. Will the gas occupy at the same temperature but at 760 ton? (213 mL)

Answer 1

0 Dalton's Law: The total pressure exerted by a gascons mixture is equal to the sum of the partiet pressures of that components prasent in the gaseous mixture. R = Pa + Plat.. .. where R = total pressure of the gas minture Pa, Pg. = Partial pressures of Companets a&b. :. Given total pressure R = 105 atm mole fraction of Hg = 005 The pressure of the Ha = Total pressure x mole fraction of Haj Pita = R X XH2 = 105 atm X0.5 = 0.45 alm .: pressure of He gas in the mixture Pha=0.75 atm. . charless law. At constant (P) pressure, the volume of a gas is dPreetly praportianal to its temparature (D) Det P= constant : volume 2 Temparature volume directly praportional to temp. VAT → V=KT y = constant =k. @ VA

Ideal gas Equation PV=ART SI mitti P= Pressure Pins Pascal, v=volume in m? - Temperature (K), R=Univerral gas constat in Zoid mamo. of moles in moles. It is simplier to solve and understood the problem while solving in SI units. @ste: Pressure P= fatm = 101325 pa, Tenparature = b c datele Ideal gas Equation PV=ARTE PV=MRT b=m-mass & P=m) MRT I SRT=M moles n= m = molar mass density 2 = m = mass : Molegular mass volume M=SKT – x 10001 - 10348/m3 density = 5=10349 x Al

идеаlѕя тоя м= get •34 % х 8314 м х 213 го» одоо1 в 101325 pa Me -o300) K x 1000 = 30-01 1/no) mol 18