(a) A rope is wrapped tightly around a wheel with a radius of 3
feet. If the radius of the wheel is increased by 3 feet to a radius
of 6 feet, by how much must the rope be lengthened to fit around
the wheel? (Round your answer to two decimal places.)
ft
(b) Consider a rope wrapped around the Earth's equator. The radius
of the Earth is about 4000 miles. That is 21,120,000 feet. Suppose
now that the rope is to be suspended exactly 9 feet above the
equator. By how much must the rope be lengthened to accomplish
this? (Round your answer to one decimal place.)
ft
thanks
(a) A rope is wrapped tightly around a wheel with a radius of 3 feet. If...
A rope is wrapped around the equator of a perfectly spherical Earth (circumference of 131,480,000 feet). This rope is cut and a piece is added in. The rope is now rearranged so that it is at a uniform height of 1 foot above the equator. How long was the piece that was added in?
In the figure, a very light rope is wrapped around a wheel o radius R = 2.0 m and does not slip. The wheel is mounted with frictionless bearings on an axle through Its center. A block of mass 14 kg is suspended from the end of the rope. When the system is released from rest it is observed that the block descends 10 m in 2.0 s. What is the moment of Inertia of the wheel?
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