Question

A mixture of ethyl iodide (b.p. 72.3) and water boils at 63.7 C. What weight of ethyl iodide would be carried over by 1 gm of steam during steam distillation

Answer 1

Question statement - A mixture of ethyl iodide (C2H51, bp 72.3°C)and water boils at 63.7°C. What weight ofethyl iodide would be carried over by 1 gram of steam during steam distillation?

The following reaction takes place during steam distillation of ethyl iodide,

$CH_3CH_2I + H_2O \rightarrow CH_3CH_2OH + HI$

Weight of water per gram of substance

$=\frac{18 \times p_{H_2O } }{MW \ of\ substance \times (760 - p_{H_2O } )}$

From the reaction, The following can be carried out:

1 mol ethyl iodide reacts with 1 mol of water, then 1 g of water has moles=

1g of H20 x 1mol H2O 189 H2O 0.055 mol H2O

So we need 0.055 mol of ethyl iodide i.e.

$=\frac{(0.055 \ mol)(156 \ g ) }{1 mol} = 8.67 \ g$

Weight of Ethyl iodide=8.67 g